CBSE Class 10 Maths Standard Coordinate Geometry Practice Questions

Choose a Coordinate Geometry topic, attempt the question first, then use the solution to revise. Topics: Distance Formula, Section Formula.

Practice coverage:155 published questions across 6 formats.

ChapterTopic

Base

In the diagram, the distance AB is found using:

Class 10 Maths coordinate geometry diagram showing points A and B connected by a distance line — Coordinate geometry diagram for deriving the distance between two points.

Select an option first. The solution will unlock after your attempt.

FAQ

Which theorem is used in the distance formula?

The distance formula is derived using Pythagoras theorem on a right triangle formed on the coordinate plane.

Base

The midpoint of $(2, 4)$ and $(6, 8)$ is:

Select an option first. The solution will unlock after your attempt.

FAQ

What is midpoint formula?

Midpoint is $(\frac{x _{1} + x _{2}}{2}, \frac{y _{1} + y _{2}}{2})$ .

Base

The point dividing $(0, 0)$ and $(6, 9)$ internally in ratio $1 : 2$ is:

Select an option first. The solution will unlock after your attempt.

FAQ

What is internal section formula used for?

It finds a point dividing a line segment internally in a given ratio.

Base

The area of triangle with vertices $(0, 0)$ , $(4, 0)$ and $(0, 3)$ is:

Select an option first. The solution will unlock after your attempt.

FAQ

What is triangle area formula?

Area is $\frac{1}{2} \times ba se \times h e i g h t$ .

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CBSE Class 10 Maths Standard Coordinate Geometry Practice Questions

Choose a Coordinate Geometry topic, attempt the question first, then use the solution to revise. Topics: Distance Formula, Section Formula.

Practice coverage:155 published questions across 6 formats.

ChapterTopic

Base

In the diagram, the distance AB is found using:

Select an option first. The solution will unlock after your attempt.

FAQ

Which theorem is used in the distance formula?

The distance formula is derived using Pythagoras theorem on a right triangle formed on the coordinate plane.

Base

The midpoint of $(2, 4)$ and $(6, 8)$ is:

Select an option first. The solution will unlock after your attempt.

FAQ

What is midpoint formula?

Midpoint is $(\frac{x _{1} + x _{2}}{2}, \frac{y _{1} + y _{2}}{2})$ .

Base

The point dividing $(0, 0)$ and $(6, 9)$ internally in ratio $1 : 2$ is:

Select an option first. The solution will unlock after your attempt.

FAQ

What is internal section formula used for?

It finds a point dividing a line segment internally in a given ratio.

Base

The area of triangle with vertices $(0, 0)$ , $(4, 0)$ and $(0, 3)$ is:

Select an option first. The solution will unlock after your attempt.

FAQ

What is triangle area formula?

Area is $\frac{1}{2} \times ba se \times h e i g h t$ .

CBSE Class 10 Maths Standard Coordinate Geometry Practice Questions

In the diagram, the distance AB is found using:

The midpoint of (2,4) and (6,8) is:

The point dividing (0,0) and (6,9) internally in ratio 1:2 is:

The area of triangle with vertices (0,0), (4,0) and (0,3) is:

CBSE Class 10 Maths Standard Coordinate Geometry Practice Questions

In the diagram, the distance AB is found using:

The midpoint of (2,4) and (6,8) is:

The point dividing (0,0) and (6,9) internally in ratio 1:2 is:

The area of triangle with vertices (0,0), (4,0) and (0,3) is:

The midpoint of $(2, 4)$ and $(6, 8)$ is:

The point dividing $(0, 0)$ and $(6, 9)$ internally in ratio $1 : 2$ is:

The area of triangle with vertices $(0, 0)$ , $(4, 0)$ and $(0, 3)$ is:

The midpoint of $(2, 4)$ and $(6, 8)$ is:

The point dividing $(0, 0)$ and $(6, 9)$ internally in ratio $1 : 2$ is:

The area of triangle with vertices $(0, 0)$ , $(4, 0)$ and $(0, 3)$ is: